Go to "Run" click "Run module. 3. How does the if statement work when you need to have multiple elif ?? This is a great site so far. Instead of using the spacebar four times just press
c=input("Enter Your Marks:") c=int(c) if c>50: print("GooD") elif c<50: print("BaD!") else: print("Enter Your marks correctly") Onofre Aquino Aug. 26, 2013, 11:29 a.m. ''' This are my code that I tried. So, we run the print("else"), and we see in the results, the string else. Let's cut to an example really quick. I looked and looked and looked. http://stackoverflow.com/questions/11186811/python-if-statement-syntax-error
getting the same problem with the elif command I'm using 3.3.2, any ideas? There's some stuff after that, but obviously the interpreter's not getting that far, so I don't think it wouldmattertoo much. It's a great step to understand how it is working with Python. For a more tangible and better look into the Python language, consider reading the following book.
i have been programming in C and C++. Example a = 20 if a >= 22: print("if") elif a >= 21: print("elif") else: print("else") Result else So, we have the variable a that equals twenty. Main Menu LQ Calendar LQ Rules LQ Sitemap Site FAQ View New Posts View Latest Posts Zero Reply Threads LQ Wiki Most Wanted Jeremy's Blog Report LQ Bug Syndicate Latest Codecademy It's so important to understand the syntax of the if statement.
Find More Posts by LinuxCrayon 12-06-2007, 02:19 PM #4 ntubski Senior Member Registered: Nov 2005 Distribution: Arch Posts: 2,995 Rep: You forgot to close the parenthesis on line 16 I will be going a long way with this. #addictive John Snow May 14, 2015, 2:45 a.m. dan March 17, 2015, 12:23 p.m. http://stackoverflow.com/questions/12732743/syntax-error-on-the-colon-in-an-if-statement Are you new to LinuxQuestions.org?
EpicYoloTime July 2, 2014, 6:58 p.m. How work in "If standartment" if i have some many variable? Click Here to receive this Complete Guide absolutely free. Download your favorite Linux distribution at LQ ISO.
That is absolute magic! read this article So, we skip past the inner print statement and continue to the elif statement. Python Colon Invalid Syntax Ok, well it doesn't have to be 4 spaces, but you must be consistent with the spaces you use to indent. Else ^ Syntaxerror Invalid Syntax Now I feel stupid.
Password Programming This forum is for all programming questions. news worked perfectly for me and got a little creative ;) print "type a number greater than 25" a =raw_input(":") if a > 25: print("good job") elif a == 25: print("that's not AwesomeMachine Linux - Software 0 05-02-2006 02:02 AM LDAP Problem Invalid DN syntax (34) steve007 Linux - Newbie 3 10-18-2005 05:03 AM Python ignores global statement? Clau Lacatus June 28, 2014, 2:35 a.m. Try Except Python
I like magical rainbow-pooping unicorns. I Used to program with C#, Js, SQL, Asp.net etc this is like an aspirin. I know other OOP languages, but this never occurred to me that in PY you need a space. have a peek at these guys Wow.
It's quite easy....for now g_econ Oct. 27, 2014, 2:55 p.m. Comment on Show Comments Kallam011011 Oct. 22, 2015, 8:21 a.m. Do I need to close of the original 'if' statement somehow?
It isn't either, which brings us to the final leg of our expanded if statement. Love this tutorial C: Harrison Defries July 2, 2014, 5:44 p.m. Just starting out, and this is surprisingly fun :) jasalia999 June 4, 2015, 6:21 a.m. Rovi Hilzawan May 11, 2013, 6:31 p.m.
It would be nice to see but, not absolutely needed. elif x >= 80: print ('your taking the piss') else: print ('you guessed correct') pacoalp May 4, 2014, 10:05 p.m. While running an "If Statement" in Python and following these directions I was getting an error "SyntaxError: multiple statements found while compiling a single statement" if this is happening to you, check my blog Often partnered with the if statement are else if and else.
Plea se use absolute paths" + " to avoid confusion. > ") 10 11 # TODO: Add a method to check if the directory exists. 12 13 add_yes = "" 14 Any ideas? LinuxCrayon View Public Profile View LQ Blog View Review Entries View HCL Entries Visit LinuxCrayon's homepage! How can i start an input for the user?
Visit the following links: Site Howto | Site FAQ | Sitemap | Register Now If you have any problems with the registration process or your account login, please contact us. Blogs Recent Entries Best Entries Best Blogs Blog List Search Blogs Home Forums HCL Reviews Tutorials Articles Register Search Search Forums Advanced Search Search Tags Search LQ Wiki Search Tutorials/Articles Search works like a charm: >>> x= 55 >>> if x >=56: print ('too high') elif x <= 54: print ('too low') elif x <= 33: print ('Im flattered') elif x >= a=20 if a>22 print "no" else print "zzz" Josh_J08 Dec. 27, 2014, 9:41 a.m.
voyciz Programming 3 04-08-2005 02:07 PM Python EXEC Statement ranger_nemo Programming 3 07-24-2003 08:31 PM All times are GMT -5. I like Python... Now, we run it through our if statement that checks to see if a is greater than or equal to 22.